0=5y^2-52y

Solution for 0=5y^2-52y equation:

0=5y^2-52y

We move all terms to the left:

0-(5y^2-52y)=0

We add all the numbers together, and all the variables

-(5y^2-52y)=0

We get rid of parentheses

-5y^2+52y=0

a = -5; b = 52; c = 0;
Δ = b2-4ac
Δ = 522-4·(-5)·0
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2704}=52$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(52)-52}{2*-5}=\frac{-104}{-10}
=10+2/5
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(52)+52}{2*-5}=\frac{0}{-10}
=0
$